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Let the point of intersection of and
be
, where
and
are the Brocard
Points, and similarly define
and
.
is the first Brocard triangle, and is inversely similar to
. It is inscribed in the Brocard Circle drawn with
as the Diameter. The triangles
,
,
and
are Isosceles Triangles with base angles
, where
is the
Brocard Angle. The sum of the areas of the Isosceles Triangles is
, the Area of Triangle
. The first Brocard triangle is in perspective with the given Triangle, with
,
, and
Concurrent. The Median Point of the first Brocard triangle is the Median Point
of the original
triangle. The Brocard triangles are in perspective at
.
Let ,
, and
and
,
, and
be the Circles intersecting in the Brocard
Points
and
, respectively. Let the two circles
and
tangent at
to
and
,
and passing respectively through
and
, meet again at
. The triangle
is the second Brocard triangle.
Each Vertex of the second Brocard triangle lies on the second Brocard Circle.
The two Brocard triangles are in perspective at .
See also Steiner Points, Tarry Point
References
Johnson, R. A. Modern Geometry: An Elementary Treatise on the Geometry of the Triangle and the Circle. Boston, MA:
Houghton Mifflin, pp. 277-281, 1929.