Input:
solve(x^2-3x-2=2*mod(2))
Write:
`solve(x^2-3x-2=2*mod(2))`
Compute:
$$solve({x}^{2} - 3\ x - 2=2\ mod(2))$$
Output:
$$solve({x}^{2} - 3\ x - 2=2\ mod(2))== \frac{3}{2}+2\ n+\frac{1}{2}\ \sqrt {33}\ and\ \frac{3}{2}+2\ n-\frac{1}{2}\ \sqrt {33}$$
Result: $$\frac{3}{2}+2\ n+\frac{1}{2}\ \sqrt {33}\ and\ \frac{3}{2}+2\ n-\frac{1}{2}\ \sqrt {33}$$
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